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# hyperbolic not circular

I think you mean "\sinh^{-1}" instead of "\sin^{-1}", same for the

others.

Parting words from the person who closed the correction:

I think you mean "\sinh^{-1}" instead of "\sin^{-1}", same for the
others.
You are right -- thank you.
Jussi

**Status:**Accepted

Reference to the user who closed the correction.:

Reference to the article this correction is about:

Status of the article (was it accepted?):

1

Status of the article (is it closed?):

1

What kind of correction is this:

Error

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